TIME_TO_DINT

TIME into DOUBLE INTEGER

TIME_TO_DINT converts a value of the data type TIME into a value of the data type DINT. The time 10ms corresponds to the value 1, e.g. an input value of T#1m0s is converted to the value 6000.

Parameters

Input

Unnamed input (TIME): Input data type

Output

Unnamed output (DINT): Conversion result

Example

POU header

All input and output variables used for programming this function have been declared in the POU header. The same POU header is used for all programming languages.

	VAR
		time_value: TIME:=T#0s;
		DINT_value: DINT:=0;
	END_VAR

This example uses variables. You can also use a constant for the input variable.

POU body

time_value of the data type TIME is converted to value of the data type DOUBLE INTEGER. The result is written into the output variable DINT_value.

LD body

BODY
    WORKSPACE
        NETWORK_LIST_TYPE := NWTYPELD ;
        ACTIVE_NETWORK := 0 ;
    END_WORKSPACE
    NET_WORK
        NETWORK_TYPE := NWTYPELD ;
        NETWORK_LABEL :=  ;
        NETWORK_TITLE :=  ;
        NETWORK_HEIGHT := 5 ;
        NETWORK_BODY
B(B_F,TIME_TO_DINT!,Instance,10,2,18,4,,?D?C);
B(B_VARIN,,TIME_value,8,2,10,4,);
B(B_VAROUT,,DINT_value,18,2,20,4,);
L(1,0,1,5);
        END_NETWORK_BODY
    END_NET_WORK
END_BODY

ST body

DINT_value:=TIME_TO_DINT(time_value);