DAY_OF_WEEK0

Return the day of the week

DAY_OF_WEEK0 returns the day of the week for any date as an INT. The number 0 corresponds to Sunday, 6 to Saturday.

Parameters

Input

Unnamed input (DATE): Date

Output

Unnamed output (WORD, INT, UINT): 0 (Sunday) – 6 (Saturday)

Example

POU header

All input and output variables used for programming this function have been declared in the POU header. The same POU header is used for all programming languages.

	VAR
		DATE_value: DATE:=D#2014-04-20;
		iDAY_OF_WEEK_value: INT:=0;
	END_VAR

LD body

BODY
    WORKSPACE
        NETWORK_LIST_TYPE := NWTYPELD ;
        ACTIVE_NETWORK := 0 ;
    END_WORKSPACE
    NET_WORK
        NETWORK_TYPE := NWTYPELD ;
        NETWORK_LABEL :=  ;
        NETWORK_TITLE :=  ;
        NETWORK_HEIGHT := 5 ;
        NETWORK_BODY
B(B_F,DAY_OF_WEEK0!,,9,2,18,4,,?D?C);
B(B_VARIN,,DATE_value,7,2,9,4,);
B(B_VAROUT,,iDAY_OF_WEEK_value,18,2,20,4,);
L(1,0,1,5);
        END_NETWORK_BODY
    END_NET_WORK
END_BODY

The value iDAY_OF_WEEK_value = 0 corresponds to Sunday.

If you need an offset of five days, e.g. 5 corresponds to Sunday:

ST body

iDAY_OF_WEEK_value := DAY_OF_WEEK0(DATE_value);
(* if you want a time offset of 5 days, e.g. Sunday corresponds to 5 *)
iDAY_OF_WEEK_value := DAY_OF_WEEK0(DATE_value )+ 5 MOD 7;