Subtract TIME from DATE_AND_TIME
SUB_DT_TIME subtracts a value of the data type TIME from a value of the data type DATE_AND_TIME. The result is stored in the output variable of the data type DATE_AND_TIME.
Input
1st input: minuend
2nd input: subtrahend
Output
Result
All input and output variables used for programming this function have been declared in the POU header. The same POU header is used for all programming languages.
VAR
DT_value: DATE_AND_TIME:=DT#2011-12-24-18:29:59;
TIME_value: TIME:=T#2h35m38s560ms;
DT_result: DATE_AND_TIME:=DT#2001-01-01-00:00:00;
END_VAR
BODY
WORKSPACE
NETWORK_LIST_TYPE := NWTYPELD ;
ACTIVE_NETWORK := 0 ;
END_WORKSPACE
NET_WORK
NETWORK_TYPE := NWTYPELD ;
NETWORK_LABEL := ;
NETWORK_TITLE := ;
NETWORK_HEIGHT := 5 ;
NETWORK_BODY
B(B_VARIN,,DT_value,16,1,18,3,);
B(B_VARIN,,TIME_value,16,2,18,4,);
B(B_VAROUT,,DT_result,27,1,29,3,);
B(B_F,SUB_DT_TIME!,Instance,18,1,26,4,,?D?D?C);
L(26,2,27,2);
L(1,0,1,5);
END_NETWORK_BODY
END_NET_WORK
END_BODY
DT_result := SUB_DT_TIME(DT_value, TIME_value);