DIV_TIME_DINT

Divide TIME by DOUBLE INTEGER

DIV_TIME_DINT divides the value of the first input variable by the value of the second and writes the result into the output variable.

Parameters

Input

TIME (TIME): 1st input: dividend
DINT (DINT): 2nd input: divisor

Output

TIME (TIME): result

Example

POU header

All input and output variables used for programming this function have been declared in the POU header. The same POU header is used for all programming languages.

	VAR
		time_value_1: TIME:=T#2h;
		time_value_2: TIME:=T#0s;
		DINT_value: DINT:=6;
	END_VAR

In this example, the input variables time_value_1, DINT_value have been declared. However, you can write a constant directly at the input contact of the function instead.

POU body

time_value_1 is divided by DINT_value. The result is written in time_value_2.

LD body

BODY
    WORKSPACE
        NETWORK_LIST_TYPE := NWTYPELD ;
        ACTIVE_NETWORK := 0 ;
    END_WORKSPACE
    NET_WORK
        NETWORK_TYPE := NWTYPELD ;
        NETWORK_LABEL :=  ;
        NETWORK_TITLE :=  ;
        NETWORK_HEIGHT := 5 ;
        NETWORK_BODY
B(B_F,DIV_TIME_DINT!,Instance,9,0,17,4,,?D@'Time'?D@'DInt'?C);
B(B_VARIN,,time_value_1,7,1,9,3,);
B(B_VARIN,,DINT_value,7,2,9,4,);
B(B_VAROUT,,time_value_2,17,1,19,3,);
L(1,0,1,5);
        END_NETWORK_BODY
    END_NET_WORK
END_BODY

ST body

time_value_2:=DIV_TIME_DINT(time_value_1, DINT_value);