MUL_TIME_DINT

Multiply TIME by DOUBLE INTEGER

MUL_TIME_DINT multiplies the values of the input variables and writes the result to the output variable.

Parameters

Input

Time (TIME)

1st input: multiplicand

Dint (DINT)

2nd input: multiplicator

Output

Time (TIME)

result

Example

POU header

All input and output variables used for programming this function have been declared in the POU header. The same POU header is used for all programming languages.

	VAR
		time_value_1: TIME:=T#1s500ms;
		multiplier: DINT:=5;
		time_value_2: TIME:=T#0s;
	END_VAR

In this example, the input variables time_value and multiplier have been declared. However, you can write a constant directly at the input contact of the function instead.

POU body

time_value_1 is multiplied by multiplier. The result is written in time_value_2.

LD body

BODY
    WORKSPACE
        NETWORK_LIST_TYPE := NWTYPELD ;
        ACTIVE_NETWORK := 0 ;
    END_WORKSPACE
    NET_WORK
        NETWORK_TYPE := NWTYPELD ;
        NETWORK_LABEL :=  ;
        NETWORK_TITLE :=  ;
        NETWORK_HEIGHT := 4 ;
        NETWORK_BODY
B(B_VARIN,,time_value_1,6,1,8,3,);
B(B_VARIN,,multiplier,6,2,8,4,);
B(B_VAROUT,,time_value_2,17,1,19,3,);
B(B_F,MUL_TIME_DINT!,Instance,8,0,17,4,,?D@'Time'?D@'DInt'?C);
L(1,0,1,4);
        END_NETWORK_BODY
    END_NET_WORK
END_BODY

ST body

time_value_2:=MUL_TIME_DINT(time_value_1, multiplier);

IL body

Modified on: 2019-01-26Feedback on this pagePanasonic hotline